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Wave Optics question

2005 · Shift 0 · Q137
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Wave Optics question

2005 · Shift 0 · Q137

JEE MainPhysicsWave OpticsMCQ+4 / −1
When an unpolarized light of intensity I0{{I_0}}I0​ is incident on a polarizing sheet, the intensity of the light which does not get transmitted is
  1. A
    14 I0{1 \over 4}\,{I_0}41​I0​
  2. B
    12 I0{1 \over 2}\,{I_0}21​I0​
  3. C
    I0{I_0}I0​
  4. D
    zero
View written solutionFree

Correct answer: B

  1. Given: Unpolarized light of intensity I0I_0I0​ is incident on a polarizing sheet.

  2. Key fact: A polarizing sheet transmits only one component of the electric field. For unpolarized light, the average transmitted intensity through an ideal polarizer is I=I02.I=\frac{I_0}{2}.I=2I0​​.

  3. Therefore, the intensity not transmitted is Iblocked=I0−I=I0−I02=I02.I_\text{blocked}=I_0-I=I_0-\frac{I_0}{2}=\frac{I_0}{2}.Iblocked​=I0​−I=I0​−2I0​​=2I0​​.

  4. Option check:

    • A: 14I0\frac{1}{4}I_041​I0​ — incorrect
    • B: 12I0\frac{1}{2}I_021​I0​ — correct
    • C: I0I_0I0​ — incorrect
    • D: zero — incorrect

Hence, the intensity of light which does not get transmitted is I02.\boxed{\frac{I_0}{2}}.2I0​​​.

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