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Wave Optics question

2005 · Shift 0 · Q134
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Wave Optics question

2005 · Shift 0 · Q134

JEE MainPhysicsWave OpticsMCQ+4 / −1
A Young's double slit experiment uses a monochromatic source. The shape of the interference fringes formed on a screen is
  1. A
    circle
  2. B
    hyperbola
  3. C
    parabola
  4. D
    straight line
View written solutionFree

Correct answer: B

  1. Condition for interference fringes

    In Young’s double slit experiment, the bright and dark fringes are loci of points on the screen where the path difference between light from the two slits is constant.

    If the two slits are at S1S_1S1​ and S2S_2S2​, then for any point PPP on the screen, S2P−S1P=constant.S_2P - S_1P = \text{constant}.S2​P−S1​P=constant.

  2. Geometrical meaning of constant path difference

    The locus of a point for which the difference of distances from two fixed points is constant is a hyperbola.

    Since S1S_1S1​ and S2S_2S2​ act like the two fixed points (foci), the interference fringes are, in general, hyperbolic.

  3. Why they often appear straight in textbooks

    In the usual YDSE arrangement, the screen is placed far from the slits and the angles are small. Under this approximation, small portions of these hyperbolae look like straight, equally spaced lines.

    But the actual geometrical shape is still hyperbola.

  4. Evaluate the options

    • A: circle — Incorrect
    • B: hyperbola — Correct
    • C: parabola — Incorrect
    • D: straight line — Only an approximation in the usual setup, not the true shape
  5. Final answer

    Therefore, the shape of interference fringes formed on the screen is hyperbola.\boxed{\text{hyperbola}}.hyperbola​.

  6. Comparison with stored correct answer

    The stored correct answer is D (straight line).

    However, the exact geometrical shape of the fringes in YDSE is hyperbola. Straight fringes are obtained only as an approximate appearance under small-angle/far-screen conditions.

    Hence, I disagree with the stored answer.

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