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Vector Algebra question

2024 · 6 Apr · Shift 1 · Q86
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  5. /2024 · 6 Apr · Shift 1 · Q86

Vector Algebra question

2024 · 6 Apr · Shift 1 · Q86

JEE MainPhysicsVector AlgebraNumerical+4 / −1
For three vectors A⃗=(−xi^−6j^−2k^),B⃗=(−i^+4j^+3k^)\vec{A}=(-x \hat{i}-6 \hat{j}-2 \hat{k}), \vec{B}=(-\hat{i}+4 \hat{j}+3 \hat{k})A=(−xi^−6j^​−2k^),B=(−i^+4j^​+3k^) and C⃗=(−8i^−j^+3k^)\vec{C}=(-8 \hat{i}-\hat{j}+3 \hat{k})C=(−8i^−j^​+3k^), if A⃗⋅(B⃗×C⃗)=0\vec{A} \cdot(\vec{B} \times \vec{C})=0A⋅(B×C)=0, then value of xxx is ‾\underline{\hspace{2cm}}​.
Numerical answer
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