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Units and Measurements question

2025 · 29 Jan · Shift 2 · Q71
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Units and Measurements question

2025 · 29 Jan · Shift 2 · Q71

JEE MainPhysicsUnits and MeasurementsNumerical+4 / −1
 A physical quantity Q is related to four observables a,b,c,d as follows : Q=ab4cd\text { A physical quantity } Q \text { is related to four observables } a, b, c, d \text { as follows : }Q = \frac{ab^4}{cd} A physical quantity Q is related to four observables a,b,c,d as follows : Q=cdab4​ where, a=(60±3)Pa;b=(20±0.1)m;c=(40±0.2)Nsm−2\mathrm{a}=(60 \pm 3) \mathrm{Pa} ; \mathrm{b}=(20 \pm 0.1) \mathrm{m} ; \mathrm{c}=(40 \pm 0.2) \mathrm{Nsm}^{-2}a=(60±3)Pa;b=(20±0.1)m;c=(40±0.2)Nsm−2 and d=(50±0.1)m\mathrm{d}=(50 \pm 0.1) \mathrm{m}d=(50±0.1)m, then the percentage error in Q is x1000\frac{x}{1000}1000x​, where x=‾x=\underline{\hspace{2cm}}x=​ .
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