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Units and Measurements question

2024 · 30 Jan · Shift 2 · Q79
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Units and Measurements question

2024 · 30 Jan · Shift 2 · Q79

JEE MainPhysicsUnits and MeasurementsMCQ+4 / −1
If mass is written as m=kcPG−1/2h1/2m=k \mathrm{c}^{\mathrm{P}} G^{-1 / 2} h^{1 / 2}m=kcPG−1/2h1/2 then the value of PPP will be : (Constants have their usual meaning with kak aka dimensionless constant)
  1. A
    1/3
  2. B
    −-− 1/3
  3. C
    1/2
  4. D
    2
View written solutionFree

Correct answer: C

  1. Write dimensions of all quantities

We are given m=k cPG−1/2h1/2m = k\, c^P G^{-1/2} h^{1/2}m=kcPG−1/2h1/2 where kkk is dimensionless.

So dimensions must satisfy [M]=[c]P[G]−1/2[h]1/2[M] = [c]^P [G]^{-1/2} [h]^{1/2}[M]=[c]P[G]−1/2[h]1/2

Now,

  • Speed of light: [c]=LT−1[c] = LT^{-1}[c]=LT−1
  • Gravitational constant: [G]=M−1L3T−2[G] = M^{-1}L^3T^{-2}[G]=M−1L3T−2
  • Planck's constant: [h]=ML2T−1[h] = ML^2T^{-1}[h]=ML2T−1
  1. Find dimensions of each factor

[c]P=LPT−P[c]^P = L^P T^{-P}[c]P=LPT−P

[G]−1/2=(M−1L3T−2)−1/2=M1/2L−3/2T1[G]^{-1/2} = \left(M^{-1}L^3T^{-2}\right)^{-1/2} = M^{1/2}L^{-3/2}T^1[G]−1/2=(M−1L3T−2)−1/2=M1/2L−3/2T1

[h]1/2=(ML2T−1)1/2=M1/2L1T−1/2[h]^{1/2} = \left(ML^2T^{-1}\right)^{1/2} = M^{1/2}L^1T^{-1/2}[h]1/2=(ML2T−1)1/2=M1/2L1T−1/2

  1. Multiply all dimensions

[c]P[G]−1/2[h]1/2=(LPT−P)(M1/2L−3/2T1)(M1/2L1T−1/2)[c]^P [G]^{-1/2} [h]^{1/2} = \left(L^P T^{-P}\right)\left(M^{1/2}L^{-3/2}T^1\right)\left(M^{1/2}L^1T^{-1/2}\right)[c]P[G]−1/2[h]1/2=(LPT−P)(M1/2L−3/2T1)(M1/2L1T−1/2)

Combine powers:

  • Mass: M1/2+1/2=M1M^{1/2+1/2} = M^1M1/2+1/2=M1

  • Length: LP−3/2+1=LP−1/2L^{P-3/2+1} = L^{P-1/2}LP−3/2+1=LP−1/2

  • Time: T−P+1−1/2=T−P+1/2T^{-P+1-1/2} = T^{-P+1/2}T−P+1−1/2=T−P+1/2

Thus RHS has dimensions M1LP−1/2T−P+1/2M^1 L^{P-1/2} T^{-P+1/2}M1LP−1/2T−P+1/2

  1. Compare with dimensions of mass

Since LHS is mass, [M]=M1L0T0[M] = M^1L^0T^0[M]=M1L0T0

So, P−12=0P - \frac{1}{2} = 0P−21​=0 −P+12=0-P + \frac{1}{2} = 0−P+21​=0

Both give P=12P = \frac{1}{2}P=21​

  1. Check options

The correct option is:

C: 12\frac{1}{2}21​

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