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Units and Measurements question

2024 · 27 Jan · Shift 1 · Q77
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Units and Measurements question

2024 · 27 Jan · Shift 1 · Q77

JEE MainPhysicsUnits and MeasurementsMCQ+4 / −1
Given below are two statements : Statement (I) : Planck's constant and angular momentum have same dimensions. Statement (II) : Linear momentum and moment of force have same dimensions. In the light of the above statements, choose the correct answer from the options given below :
  1. A
    Statement I is true but Statement II is false
  2. B
    Both Statement I and Statement II are false
  3. C
    Both Statement I and Statement II are true
  4. D
    Statement I is false but Statement II is true
View written solutionFree

Correct answer: A

  1. Check Statement (I): Planck's constant and angular momentum

Planck's constant hhh has dimensions of energy ×\times× time.

[h]=[E] [t]=(ML2T−2)(T)=ML2T−1[h] = [E]\,[t] = (ML^2T^{-2})(T) = ML^2T^{-1}[h]=[E][t]=(ML2T−2)(T)=ML2T−1

Angular momentum is:

L=r×pL = r \times pL=r×p

where [r]=L[r] = L[r]=L and linear momentum [p]=MLT−1[p] = MLT^{-1}[p]=MLT−1.

So,

[angular momentum]=L⋅MLT−1=ML2T−1[\text{angular momentum}] = L \cdot MLT^{-1} = ML^2T^{-1}[angular momentum]=L⋅MLT−1=ML2T−1

Thus,

[h]=[angular momentum][h] = [\text{angular momentum}][h]=[angular momentum]

So Statement (I) is true.


  1. Check Statement (II): Linear momentum and moment of force

Linear momentum has dimensions:

[p]=MLT−1[p] = MLT^{-1}[p]=MLT−1

Moment of force (torque) is:

τ=F×r\tau = F \times rτ=F×r

Since force has dimensions

[F]=MLT−2[F] = MLT^{-2}[F]=MLT−2

therefore,

[τ]=(MLT−2)(L)=ML2T−2[\tau] = (MLT^{-2})(L) = ML^2T^{-2}[τ]=(MLT−2)(L)=ML2T−2

Now compare:

  • Linear momentum: MLT−1MLT^{-1}MLT−1
  • Moment of force: ML2T−2ML^2T^{-2}ML2T−2

These are not the same.

So Statement (II) is false.


  1. Conclusion
  • Statement (I) is true
  • Statement (II) is false

Therefore, the correct option is:

A\boxed{\text{A}}A​

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