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Units and Measurements question

2024 · 9 Apr · Shift 1 · Q63
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Units and Measurements question

2024 · 9 Apr · Shift 1 · Q63

JEE MainPhysicsUnits and MeasurementsMCQ+4 / −1
The dimensional formula of latent heat is :
  1. A
    [M0LT−2]\left[\mathrm{M}^{\mathrm{0}} \mathrm{LT}^{-2}\right][M0LT−2]
  2. B
    [MLT−2]\left[\mathrm{MLT}^{-2}\right][MLT−2]
  3. C
    [M0 L2 T−2]\left[\mathrm{M}^0 \mathrm{~L}^2 \mathrm{~T}^{-2}\right][M0 L2 T−2]
  4. D
    [ML2 T−2]\left[\mathrm{ML}^2 \mathrm{~T}^{-2}\right][ML2 T−2]
View written solutionFree

Correct answer: C

  1. Recall the definition of latent heat

    Latent heat (specific latent heat) is defined as the amount of heat required to change the phase of unit mass of a substance without changing its temperature.

    L=QmL = \frac{Q}{m}L=mQ​

    where:

    • QQQ = heat energy
    • mmm = mass
  2. Write dimensions of heat energy

    Heat is a form of energy, so its dimensions are the same as work/energy:

    [Q]=[ML2T−2][Q] = [ML^2T^{-2}][Q]=[ML2T−2]

  3. Divide by mass

    Since

    L=QmL = \frac{Q}{m}L=mQ​

    its dimensional formula is

    [L]=[ML2T−2][M]=[M0L2T−2][L] = \frac{[ML^2T^{-2}]}{[M]} = [M^0L^2T^{-2}][L]=[M][ML2T−2]​=[M0L2T−2]

  4. Match with the options

    The correct option is:

    [M0L2T−2]\boxed{[M^0L^2T^{-2}]}[M0L2T−2]​

    This corresponds to Option C.

  5. Comparison with stored answer

    Stored correct answer: C

    My derived answer: C

    Hence, they agree.

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