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Simple Harmonic Motion question

2005 · Shift 0 · Q142
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  5. /2005 · Shift 0 · Q142

Simple Harmonic Motion question

2005 · Shift 0 · Q142

JEE MainPhysicsSimple Harmonic MotionMCQ+4 / −1
Two simple harmonic motions are represented by the equations y1=0.1 sin⁡(100πt+π3){y_1} = 0.1\,\sin \left( {100\pi t + {\pi \over 3}} \right)y1​=0.1sin(100πt+3π​) and y2=0.1 cos⁡ πt.{y_2} = 0.1\,\cos \,\pi t.y2​=0.1cosπt. The phase difference of the velocity of particle 111 with respect to the velocity of particle 222 is
  1. A
    π3{\pi \over 3}3π​
  2. B
    −π6{{ - \pi } \over 6}6−π​
  3. C
    π6{\pi \over 6}6π​
  4. D
    −π3{{ - \pi } \over 3}3−π​
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