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Simple Harmonic Motion question

2004 · Shift 0 · Q179
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Simple Harmonic Motion question

2004 · Shift 0 · Q179

JEE MainPhysicsSimple Harmonic MotionMCQ+4 / −1
A particle of mass mmm is attached to a spring (of spring constant kkk) and has a natural angular frequency ω0.{\omega _0}.ω0​. An external force F(t)F(t)F(t) proportional to cos⁡ ωt(ωeω0)\cos \,\omega t\left( {\omega e {\omega _0}} \right)cosωt(ωeω0​) is applied to the oscillator. The time displacement of the oscillator will be proportional to
  1. A
    1m(ω02+ω2){1 \over {m\left( {\omega _0^2 + {\omega ^2}} \right)}}m(ω02​+ω2)1​
  2. B
    1m(ω02−ω2){1 \over {m\left( {\omega _0^2 - {\omega ^2}} \right)}}m(ω02​−ω2)1​
  3. C
    mω02−ω2{m \over {\omega _0^2 - {\omega ^2}}}ω02​−ω2m​
  4. D
    mω02+ω2{m \over {\omega _0^2 + {\omega ^2}}}ω02​+ω2m​
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