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Rotational Motion question

2024 · 31 Jan · Shift 2 · Q82

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JEE Main
Physics
Rotational Motion
2024 · 31 Jan · Shift 2 · Q82

Rotational Motion question

2024 · 31 Jan · Shift 2 · Q82

JEE MainPhysicsRotational MotionNumerical+4 / −1

A body of mass '

m

' is projected with a speed '

u

' making an angle of

45^{\circ}

with the ground. The angular momentum of the body about the point of projection, at the highest point is expressed as

\frac{\sqrt{2} m u^3}{X g}

. The value of '

X

' is

\underline{\hspace{2cm}}

.

Numerical answer

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