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Rotational Motion question

2023 · 1 Feb · Shift 2 · Q69

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JEE Main
Physics
Rotational Motion
2023 · 1 Feb · Shift 2 · Q69

Rotational Motion question

2023 · 1 Feb · Shift 2 · Q69

JEE MainPhysicsRotational MotionNumerical+4 / −1

Moment of inertia of a disc of mass '

M

' and radius '

R

' about any of its diameter is

\frac{M R^{2}}{4}

. The moment of inertia of this disc about an axis normal to the disc and passing through a point on its edge will be,

\frac{x}{2}

MR

^{2}

. The value of

x

is

\underline{\hspace{2cm}}

.

Numerical answer

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