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Rotational Motion question

2023 · 24 Jan · Shift 2 · Q67
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  5. /2023 · 24 Jan · Shift 2 · Q67

Rotational Motion question

2023 · 24 Jan · Shift 2 · Q67

JEE MainPhysicsRotational MotionNumerical+4 / −1
A uniform solid cylinder with radius R and length L has moment of inertia I 1_11​, about the axis of the cylinder. A concentric solid cylinder of radius R′=R2R'=\frac{R}{2}R′=2R​ and length L′=L2L'=\frac{L}{2}L′=2L​ is carved out of the original cylinder. If I 2_22​ is the moment of inertia of the carved out portion of the cylinder then I1I2=‾\frac{I_1}{I_2}=\underline{\hspace{2cm}}I2​I1​​=​. (Both I 1_11​ and I 2_22​ are about the axis of the cylinder)
Numerical answer
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