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Rotational Motion question

2020 · 3 Sep · Shift 1 · Q63
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  5. /2020 · 3 Sep · Shift 1 · Q63

Rotational Motion question

2020 · 3 Sep · Shift 1 · Q63

JEE MainPhysicsRotational MotionMCQ+4 / −1
Moment of inertia of a cylinder of mass M, length L and radius R about an axis passing through its centre and perpendicular to the axis of the cylinder is I = M(R24+L212)M\left( {{{{R^2}} \over 4} + {{{L^2}} \over {12}}} \right)M(4R2​+12L2​). If such a cylinder is to be made for a given mass of a material, the ratio LR{L \over R}RL​ for it to have minimum possible I is
  1. A
    32{3 \over 2}23​
  2. B
    32\sqrt {{3 \over 2}}23​​
  3. C
    23\sqrt {{2 \over 3}}32​​
  4. D
    23{{2 \over 3}}32​
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