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Rotational Motion question

2019 · 11 Jan · Shift 1 · Q49
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  5. /2019 · 11 Jan · Shift 1 · Q49

Rotational Motion question

2019 · 11 Jan · Shift 1 · Q49

JEE MainPhysicsRotational MotionMCQ+4 / −1
A slab is subjected to two forces F1→\overrightarrow {{F_1}}F1​​ and F2→\overrightarrow {{F_2}}F2​​ of same magnitude F as shown in the figure. Force F2→\overrightarrow {{F_2}}F2​​ is in XY-plane while force F1→\overrightarrow {{F_1}}F1​​ acts along z = axis at the point (2i→+3j→).\left( {2\overrightarrow i + 3\overrightarrow j } \right).(2i+3j​).. The moment of these forces about point O will be : JEE Main 2019 (Online) 11th January Morning Slot Physics - Rotational Motion Question 184 English
  1. A
    (3i^−2j^−3k^)F\left( {3\widehat i - 2\widehat j - 3\widehat k} \right)F(3i−2j​−3k)F
  2. B
    (3i^+2j^−3k^)F\left( {3\widehat i + 2\widehat j - 3\widehat k} \right)F(3i+2j​−3k)F
  3. C
    (3i^+2j^+3k^)F\left( {3\widehat i + 2\widehat j + 3\widehat k} \right)F(3i+2j​+3k)F
  4. D
    (3i^−2j^+3k^)F\left( {3\widehat i - 2\widehat j + 3\widehat k} \right)F(3i−2j​+3k)F
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