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Properties of Matter question

2022 · 26 Jun · Shift 2 · Q52
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  5. /2022 · 26 Jun · Shift 2 · Q52

Properties of Matter question

2022 · 26 Jun · Shift 2 · Q52

JEE MainPhysicsProperties of MatterMCQ+4 / −1
If p is the density and η\etaη is coefficient of viscosity of fluid which flows with a speed v in the pipe of diameter d, the correct formula for Reynolds number Re is :
  1. A
    Re=ηdρv{R_e} = {{\eta d} \over {\rho v}}Re​=ρvηd​
  2. B
    Re=ρvηd{R_e} = {{\rho v} \over {\eta d}}Re​=ηdρv​
  3. C
    Re=ρvdη{R_e} = {{\rho vd} \over \eta }Re​=ηρvd​
  4. D
    Re=ηρvd{R_e} = {\eta \over {\rho vd}}Re​=ρvdη​
View written solutionFree

Correct answer: C

  1. Recall the definition of Reynolds number

    For fluid flow in a pipe, the Reynolds number is Re=inertial forceviscous forceR_e = \frac{\text{inertial force}}{\text{viscous force}}Re​=viscous forceinertial force​ and its standard formula is Re=ρvLηR_e = \frac{\rho v L}{\eta}Re​=ηρvL​ where:

    • ρ\rhoρ = density of fluid
    • vvv = speed of fluid
    • LLL = characteristic length
    • η\etaη = coefficient of viscosity
  2. Identify the characteristic length for flow in a pipe

    For flow through a pipe, the characteristic length is the diameter of the pipe, i.e. L=dL = dL=d

    Therefore, Re=ρvdηR_e = \frac{\rho v d}{\eta}Re​=ηρvd​

  3. Match with the given options

    Compare with the options:

    • A: Re=ηdρvR_e = \frac{\eta d}{\rho v}Re​=ρvηd​
    • B: Re=ρvηdR_e = \frac{\rho v}{\eta d}Re​=ηdρv​
    • C: Re=ρvdηR_e = \frac{\rho v d}{\eta}Re​=ηρvd​
    • D: Re=ηρvdR_e = \frac{\eta}{\rho v d}Re​=ρvdη​

    The correct match is: C\boxed{C}C​

  4. Check dimensionlessness

    Reynolds number must be dimensionless.

    For option C: ρvdη=(ML−3)(LT−1)(L)ML−1T−1=1\frac{\rho v d}{\eta} = \frac{(M L^{-3})(L T^{-1})(L)}{M L^{-1} T^{-1}} = 1ηρvd​=ML−1T−1(ML−3)(LT−1)(L)​=1 so it is dimensionless, as required.

Hence, the correct formula is Re=ρvdη\boxed{R_e = \frac{\rho v d}{\eta}}Re​=ηρvd​​

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