JEE MainPhysicsProperties of MatterNumerical+4 / −1
Two separate wires A and B are stretched by 2 mm and 4 mm respectively, when they are subjected to a force of 2 N. Assume that both the wires are made up of same material and the radius of wire B is 4 times that of the radius of wire A. The length of the wires A and B are in the ratio of a : b. Then a/b can be expressed as 1/x where x is .
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Correct answer: 32
- Use the formula for extension of a wire
For a wire under tension,
where:
- = extension,
- = applied force,
- = original length,
- = cross-sectional area,
- = Young's modulus.
Since both wires are made of the same material, is same for both. Also, both are subjected to the same force .
So,
- Write the ratio of extensions
Given:
- Wire A stretches by
- Wire B stretches by
Hence,
Now,
- Use the radius information
Radius of wire B is 4 times radius of wire A:
Area is proportional to square of radius:
Therefore,
- Substitute into the extension ratio
So,
Given , therefore
This is of the form
so,
- Comparison with stored answer
Derived answer:
Stored correct answer:
They match.
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