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Magnetics question

2024 · 29 Jan · Shift 2 · Q89
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Magnetics question

2024 · 29 Jan · Shift 2 · Q89

JEE MainPhysicsMagneticsNumerical+4 / −1
A charge of 4.0μC4.0 \mu \mathrm{C}4.0μC is moving with a velocity of 4.0×106 ms−14.0 \times 10^6 \mathrm{~ms}^{-1}4.0×106 ms−1 along the positive yyy axis under a magnetic field B⃗\vec{B}B of strength (2k^)T(2 \hat{k}) \mathrm{T}(2k^)T. The force acting on the charge is xi^Nx \hat{i} Nxi^N. The value of xxx is ‾\underline{\hspace{2cm}}​.
Numerical answer
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