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Magnetics question

2024 · 31 Jan · Shift 1 · Q82
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Magnetics question

2024 · 31 Jan · Shift 1 · Q82

JEE MainPhysicsMagneticsNumerical+4 / −1
An electron moves through a uniform magnetic field B⃗=B0i^+2B0j^T\vec{B}=B_0 \hat{i}+2 B_0 \hat{j} TB=B0​i^+2B0​j^​T. At a particular instant of time, the velocity of electron is u⃗=3i^+5j^ m/s\vec{u}=3 \hat{i}+5 \hat{j} \mathrm{~m} / \mathrm{s}u=3i^+5j^​ m/s. If the magnetic force acting on electron is F⃗=5ek^N\vec{F}=5 e \hat{k} NF=5ek^N, where eee is the charge of electron, then the value of B0B_0B0​ is ‾\underline{\hspace{2cm}}​TTT.
Numerical answer
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