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Magnetics question

2021 · 26 Aug · Shift 1 · Q67
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  5. /2021 · 26 Aug · Shift 1 · Q67

Magnetics question

2021 · 26 Aug · Shift 1 · Q67

JEE MainPhysicsMagneticsNumerical+4 / −1
Two short magnetic dipoles m1 and m2 each having magnetic moment of 1 Am2 are placed at point O and P respectively. The distance between OP is 1 meter. The torque experienced by the magnetic dipole m2 due to the presence of m1 is ........... ×\times× 10 −-− 7 Nm. JEE Main 2021 (Online) 26th August Morning Shift Physics - Magnetic Effect of Current Question 121 English
Numerical answer
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Correct answer: 1

  1. Torque on a magnetic dipole

    The torque on dipole m2m_2m2​ placed in the magnetic field of dipole m1m_1m1​ is τ=m2Bsin⁡θ\tau = m_2 B \sin\thetaτ=m2​Bsinθ where θ\thetaθ is the angle between m⃗2\vec m_2m2​ and the magnetic field due to m1m_1m1​.

  2. Magnetic field due to a short magnetic dipole

    For a dipole of magnetic moment m1m_1m1​ at distance rrr on its equatorial line, the magnetic field is B=μ04πm1r3B = \frac{\mu_0}{4\pi}\frac{m_1}{r^3}B=4πμ0​​r3m1​​

    Given: m1=1 A m2,m2=1 A m2,r=OP=1 mm_1 = 1\,\text{A m}^2, \quad m_2 = 1\,\text{A m}^2, \quad r = OP = 1\,\text{m}m1​=1A m2,m2​=1A m2,r=OP=1m and μ04π=10−7\frac{\mu_0}{4\pi} = 10^{-7}4πμ0​​=10−7

    So, B=10−7⋅113=10−7 TB = 10^{-7}\cdot \frac{1}{1^3} = 10^{-7}\,\text{T}B=10−7⋅131​=10−7T

  3. Maximum torque

    Since only the magnitudes are given, torque is taken for the perpendicular orientation: sin⁡θ=1\sin\theta = 1sinθ=1

    Hence, τ=m2B=1×10−7=10−7 N m\tau = m_2 B = 1 \times 10^{-7} = 10^{-7}\,\text{N m}τ=m2​B=1×10−7=10−7N m

  4. Required integer

    The torque is τ=1×10−7 N m\tau = 1 \times 10^{-7}\,\text{N m}τ=1×10−7N m

    Therefore, the required integer is 1.

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