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Magnetics question

2009 · Shift 0 · Q57
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Magnetics question

2009 · Shift 0 · Q57

JEE MainPhysicsMagneticsMCQ+4 / −1
A current loop ABCDABCDABCD is held fixed on the plane of the paper as shown in the figure. The arcs BCBCBC(radius =b= b=b) and DADADA(radius =a=a=a) of the loop are joined by two straight wires ABABAB and CDCDCD. A steady current III is flowing in the loop. Angle made by ABABAB and CDCDCD at the origin OOO is 30∘.{30^ \circ }.30∘. Another straight thin wire steady current I1{I_1}I1​ flowing out of the plane of the paper is kept at the origin. AIEEE 2009 Physics - Magnetic Effect of Current Question 194 English Due to the presence of the current I1{I_1}I1​ at the origin:
  1. A
    The forces on ADADAD are BCBCBC are zero.
  2. B
    The magnitude of the net force on the loop is given by I1I4πμ0[2(b−a)+π3(a+b)].{{{I_1}I} \over {4\pi }}{\mu _0}\left[ {2\left( {b - a} \right) + \frac{\pi }{3}\left( {a + b} \right)} \right].4πI1​I​μ0​[2(b−a)+3π​(a+b)].
  3. C
    The magnitude of the net force on the loop is given by μ0II124ab(b−a).{{{\mu _0}I{I_1}} \over {24ab}}\left( {b - a} \right).24abμ0​II1​​(b−a).
  4. D
    The forces on ABABAB and DCDCDC are zero.
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