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Laws of Motion question

2003 · Shift 0 · Q176
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Laws of Motion question

2003 · Shift 0 · Q176

JEE MainPhysicsLaws of MotionMCQ+4 / −1
A marble block of mass 2kg2kg2kg lying on ice when given a velocity of 6m/s6m/s6m/s is stopped by friction in 10s.10s.10s. Then the coefficient of friction is
  1. A
    0.020.020.02
  2. B
    0.030.030.03
  3. C
    0.040.040.04
  4. D
    0.060.060.06
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