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Heat and Thermodynamics question

2019 · 12 Apr · Shift 1 · Q71
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Heat and Thermodynamics question

2019 · 12 Apr · Shift 1 · Q71

JEE MainPhysicsHeat and ThermodynamicsMCQ+4 / −1
When M1 gram of ice at –10oC (specific heat = 0.5 cal g–1 oC–1 ) is added to M2 gram of water at 50C, finally no ice is left and the water is at 0°C. The value of latent heat of ice, in cal g–1 is :
  1. A
    50M2M1−5{{50{M_2}} \over {{M_1}}} - 5M1​50M2​​−5
  2. B
    50M2M1{{50{M_2}} \over {{M_1}}}M1​50M2​​
  3. C
    5M2M1−5{{5{M_2}} \over {{M_1}}} - 5M1​5M2​​−5
  4. D
    5M1M2−50{{5{M_1}} \over {{M_2}}} - 50M2​5M1​​−50
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