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Heat and Thermodynamics question

2019 · 9 Apr · Shift 2 · Q48
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Heat and Thermodynamics question

2019 · 9 Apr · Shift 2 · Q48

JEE MainPhysicsHeat and ThermodynamicsMCQ+4 / −1
Two materials having coefficients of thermal conductivity '3K' and 'K' and thickness 'd' and '3d', respectively, are joined to form a slab as shown in the figure. The temperatures of the outer surfaces are 'θ\thetaθ 2' and 'θ\thetaθ 1' respectively, (θ\thetaθ 2 > θ\thetaθ 1). The temperature at the interface is :- JEE Main 2019 (Online) 9th April Evening Slot Physics - Heat and Thermodynamics Question 334 English
  1. A
    θ110+9θ210{{{\theta _1}} \over {10}} + {{9{\theta _2}} \over {10}}10θ1​​+109θ2​​
  2. B
    θ2+θ12{{{\theta _2} + {\theta _1}} \over 2}2θ2​+θ1​​
  3. C
    θ16+5θ26{{{\theta _1}} \over {6}} + {{5{\theta _2}} \over {6}}6θ1​​+65θ2​​
  4. D
    θ13+2θ23{{{\theta _1}} \over {3}} + {{2{\theta _2}} \over {3}}3θ1​​+32θ2​​
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