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Gravitation question

2025 · 23 Jan · Shift 2 · Q75

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JEE Main
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Gravitation
2025 · 23 Jan · Shift 2 · Q75

Gravitation question

2025 · 23 Jan · Shift 2 · Q75

JEE MainPhysicsGravitationNumerical+4 / −1

A satellite of mass

\frac{M}{2}

is revolving around earth in a circular orbit at a height of

\frac{R}{3}

from earth surface. The angular momentum of the satellite is

\mathrm{M} \sqrt{\frac{\mathrm{GMR}}{x}}

. The value of

x

is

\underline{\hspace{2cm}}

, where M and R are the mass and radius of earth, respectively. ( G is the gravitational constant)

Numerical answer

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