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Gravitation question

2025 · 2 Apr · Shift 2 · Q75
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Gravitation question

2025 · 2 Apr · Shift 2 · Q75

JEE MainPhysicsGravitationNumerical+4 / −1
A satellite of mass 1000 kg is launched to revolve around the earth in an orbit at a height of 270 km from the earth's surface. Kinetic energy of the satellite in this orbit is ‾×1010 J\underline{\hspace{2cm}}\times 10^{10} \mathrm{~J}​×1010 J. (Mass of earth =6×1024 kg=6 \times 10^{24} \mathrm{~kg}=6×1024 kg, Radius of earth =6.4×106 m=6.4 \times 10^6 \mathrm{~m}=6.4×106 m, Gravitational constant =6.67×10−11Nm2 kg−2=6.67 \times 10^{-11} \mathrm{Nm}^2 \mathrm{~kg}^{-2}=6.67×10−11Nm2 kg−2 )
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