Given

• Two satellites $A$ and $B$ move around Earth in the same orbit.
• Mass of satellite $A$ is twice the mass of satellite $B$.
• Let the common orbital radius be $r$.

Speed of a satellite in a circular orbit The orbital speed is $v = \sqrt{\frac{GM}{r}},$ where $M$ is the mass of Earth.

Since both satellites are in the same orbit, both have the same $r$. Also, $G$ and $M$ are constants. Therefore, $v_A = v_B = \sqrt{\frac{GM}{r}}.$

So, speed is the same for both satellites.

Check other options

Let mass of satellite $B$ be $m$. Then mass of $A$ is $2m$.

(A) Potential energy

Gravitational potential energy is $U = -\frac{GMm}{r}.$ For $A$: $U_A = -\frac{GM(2m)}{r} = -\frac{2GMm}{r}.$ For $B$: $U_B = -\frac{GMm}{r}.$ Hence, $U_A \ne U_B$.

(B) Kinetic energy

$K = \frac{1}{2}mv^2 = \frac{GMm}{2r}.$ For $A$: $K_A = \frac{GM(2m)}{2r} = \frac{GMm}{r}.$ For $B$: $K_B = \frac{GMm}{2r}.$ Hence, $K_A \ne K_B$.

(C) Total energy

For a satellite in circular orbit, $E = K + U = -\frac{GMm}{2r}.$ For $A$: $E_A = -\frac{GM(2m)}{2r} = -\frac{GMm}{r}.$ For $B$: $E_B = -\frac{GMm}{2r}.$ Hence, $E_A \ne E_B$.

Conclusion The only quantity same for both satellites is: $\boxed{\text{Speed}}$

Comparison with stored correct answer Stored correct answer: $D$

Our derived answer: $D$

So, the derived answer agrees with the stored correct answer.