1. Condition for minimum deviation in a prism

For a prism of angle $A$:

• Angles of refraction inside prism are $r_1$ and $r_2$.
• In general, $r_1 + r_2 = A$
• At minimum deviation, $i = e \quad \text{and} \quad r_1 = r_2 = \frac{A}{2}$

This is the symmetric condition.

2. Check each statement

Statement A: The refracted ray inside prism becomes parallel to the base.

At minimum deviation, the path inside the prism is symmetric. In the standard prism geometry, this makes the refracted ray inside the prism parallel to the base.

So, A is correct.

Statement B: Larger angle prisms provide smaller angle of minimum deviation.

For a prism, $\mu = \frac{\sin\left(\frac{A+\delta_m}{2}\right)}{\sin\left(\frac{A}{2}\right)}$ For fixed refractive index $\mu$, increasing prism angle $A$ increases minimum deviation $\delta_m$.

So larger prism angle does not give smaller minimum deviation.

Hence, B is false.

Statement C: Angle of incidence and angle of emergence becomes equal.

At minimum deviation, $i=e$ So, C is correct.

Statement D: There are always two sets of angle of incidence for which deviation will be same except at minimum deviation setting.

The deviation vs incidence graph is symmetric about the minimum deviation point. Therefore, for any deviation greater than minimum deviation, there are two possible angles of incidence.

So, D is correct.

Statement E: Angle of refraction becomes double of prism angle.

At minimum deviation, $r_1=r_2=\frac{A}{2}$ Thus angle of refraction is half the prism angle, not double.

So, E is false.

3. Correct set of statements

Correct statements are: $A,\ C,\ D$

So the correct option is: $\boxed{\text{D}}$

4. Comparison with stored answer

Stored correct answer: D

My derived answer: D

They match.