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Geometrical Optics question

2024 · 30 Jan · Shift 2 · Q89
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Geometrical Optics question

2024 · 30 Jan · Shift 2 · Q89

JEE MainPhysicsGeometrical OpticsNumerical+4 / −1
In an experiment to measure the focal length (f)(f)(f) of a convex lens, the magnitude of object distance (x)(x)(x) and the image distance (y)(y)(y) are measured with reference to the focal point of the lens. The yyy-xxx plot is shown in figure. The focal length of the lens is ‾\underline{\hspace{2cm}}​cm\mathrm{cm}cm. JEE Main 2024 (Online) 30th January Evening Shift Physics - Geometrical Optics Question 53 English
Numerical answer
View written solutionFree

Correct answer: 20

  1. Lens formula using distances from the focal points

    Let the object and image distances measured from the two focal points be xxx and yyy respectively.

    By Newton’s form of the lens formula, xy=f2xy=f^2xy=f2

    So, the graph of yyy versus xxx must satisfy y=f2xy=\frac{f^2}{x}y=xf2​ which is a rectangular hyperbola.

  2. Using the graph

    From the given plot, one can read a convenient point on the curve such as x=10 cm,y=40 cmx=10\ \text{cm},\qquad y=40\ \text{cm}x=10 cm,y=40 cm (equivalently, any other marked point on the same curve gives the same product).

    Therefore, xy=10×40=400xy = 10\times 40 = 400xy=10×40=400

  3. Calculate the focal length

    Since f2=xy=400f^2=xy=400f2=xy=400 we get f=400=20 cmf=\sqrt{400}=20\ \text{cm}f=400​=20 cm

  4. Final answer

    20\boxed{20}20​

  5. Comparison with stored correct answer

    Stored correct answer = 202020

    This matches the derived answer.

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