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Geometrical Optics question

2023 · 12 Apr · Shift 1 · Q51
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  5. /2023 · 12 Apr · Shift 1 · Q51

Geometrical Optics question

2023 · 12 Apr · Shift 1 · Q51

JEE MainPhysicsGeometrical OpticsMCQ+4 / −1
An ice cube has a bubble inside. When viewed from one side the apparent distance of the bubble is 12 cm12 \mathrm{~cm}12 cm. When viewed from the opposite side, the apparent distance of the bubble is observed as 4 cm4 \mathrm{~cm}4 cm. If the side of the ice cube is 24 cm24 \mathrm{~cm}24 cm, the refractive index of the ice cube is
  1. A
    32\frac{3}{2}23​
  2. B
    43\frac{4}{3}34​
  3. C
    23\frac{2}{3}32​
  4. D
    65\frac{6}{5}56​
View written solutionFree

Correct answer: A

  1. Set up the geometry

Let the real distance of the bubble from one face be xxx. Then its distance from the opposite face is 24−x24 - x24−x because the side of the ice cube is 24 cm24\,\text{cm}24cm.

  1. Use apparent depth formula

For an object inside a denser medium viewed from air, apparent depth=real depthμ\text{apparent depth} = \frac{\text{real depth}}{\mu}apparent depth=μreal depth​ where μ\muμ is the refractive index of ice.

  1. Observation from the first side

Apparent distance is 12 cm12\,\text{cm}12cm, so xμ=12\frac{x}{\mu} = 12μx​=12 Hence, x=12μx = 12\mux=12μ

  1. Observation from the opposite side

Apparent distance is 4 cm4\,\text{cm}4cm, so 24−xμ=4\frac{24-x}{\mu} = 4μ24−x​=4 Hence, 24−x=4μ24 - x = 4\mu24−x=4μ

  1. Substitute x=12μx = 12\mux=12μ

24−12μ=4μ24 - 12\mu = 4\mu24−12μ=4μ 24=16μ24 = 16\mu24=16μ μ=2416=32\mu = \frac{24}{16} = \frac{3}{2}μ=1624​=23​

  1. Check with options

μ=32\mu = \frac{3}{2}μ=23​ So the correct option is A.

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