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Geometrical Optics question

2021 · 26 Feb · Shift 2 · Q56
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  5. /2021 · 26 Feb · Shift 2 · Q56

Geometrical Optics question

2021 · 26 Feb · Shift 2 · Q56

JEE MainPhysicsGeometrical OpticsMCQ+4 / −1
The incident ray, reflected ray and the outward drawn normal are denoted by the unit vectors a→\overrightarrow aa, b→\overrightarrow bb and c→\overrightarrow cc respectively. Then choose the correct relation for these vectors.
  1. A
    b→\overrightarrow bb=a→\overrightarrow aa + 2 c→\overrightarrow cc
  2. B
    b→\overrightarrow bb=a→−\overrightarrow a -a− 2 (a→\overrightarrow aa. c→\overrightarrow cc) c→\overrightarrow cc
  3. C
    b→\overrightarrow bb = 2 a→\overrightarrow aa+c→\overrightarrow cc
  4. D
    b→\overrightarrow bb=a→−c→\overrightarrow a -\overrightarrow ca−c
View written solutionFree

Correct answer: B

  1. Idea of reflection in vector form

When a ray with unit direction vector a⃗\vec aa is reflected from a surface whose outward unit normal is c⃗\vec cc, the component of a⃗\vec aa parallel to the surface remains unchanged, while the component along the normal reverses sign.

  1. Resolve the incident direction into normal and tangential parts

The component of a⃗\vec aa along c⃗\vec cc is

(a⃗⋅c⃗) c⃗.(\vec a \cdot \vec c)\,\vec c.(a⋅c)c.

So the tangential component is

a⃗−(a⃗⋅c⃗) c⃗.\vec a - (\vec a \cdot \vec c)\,\vec c.a−(a⋅c)c.
  1. Apply reflection rule

After reflection:

  • tangential component stays same,
  • normal component changes sign.

Hence reflected vector b⃗\vec bb is

b⃗=[a⃗−(a⃗⋅c⃗)c⃗]−(a⃗⋅c⃗)c⃗.\vec b = \left[\vec a - (\vec a \cdot \vec c)\vec c\right] - (\vec a \cdot \vec c)\vec c.b=[a−(a⋅c)c]−(a⋅c)c.

Therefore,

b⃗=a⃗−2(a⃗⋅c⃗)c⃗.\vec b = \vec a - 2(\vec a \cdot \vec c)\vec c.b=a−2(a⋅c)c.
  1. Match with options
  • A: b⃗=a⃗+2c⃗\vec b = \vec a + 2\vec cb=a+2c
    Incorrect, since it ignores the projection factor (a⃗⋅c⃗)(\vec a \cdot \vec c)(a⋅c).

  • B: b⃗=a⃗−2(a⃗⋅c⃗)c⃗\vec b = \vec a - 2(\vec a \cdot \vec c)\vec cb=a−2(a⋅c)c
    Correct.

  • C: b⃗=2a⃗+c⃗\vec b = 2\vec a + \vec cb=2a+c
    Incorrect.

  • D: b⃗=a⃗−c⃗\vec b = \vec a - \vec cb=a−c
    Incorrect.

  1. Final answer

The correct relation is

b⃗=a⃗−2(a⃗⋅c⃗)c⃗\boxed{\vec b = \vec a - 2(\vec a \cdot \vec c)\vec c}b=a−2(a⋅c)c​

So the correct option is B.

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