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Electrostatics question

2023 · 10 Apr · Shift 2 · Q62
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Electrostatics question

2023 · 10 Apr · Shift 2 · Q62

JEE MainPhysicsElectrostaticsNumerical+4 / −1
An electron revolves around an infinite cylindrical wire having uniform linear charge density 2×10−8Cm−12 \times 10^{-8} \mathrm{C} \mathrm{m}^{-1}2×10−8Cm−1 in circular path under the influence of attractive electrostatic field as shown in the figure. The velocity of electron with which it is revolving is ‾\underline{\hspace{2cm}}​×106 m s−1\times 10^{6} \mathrm{~m} \mathrm{~s}^{-1}×106 m s−1. Given mass of electron =9×10−31 kg=9 \times 10^{-31} \mathrm{~kg}=9×10−31 kg JEE Main 2023 (Online) 10th April Evening Shift Physics - Electrostatics Question 76 English
Numerical answer
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