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Electrostatics question

2002 · Shift 0 · Q161
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Electrostatics question

2002 · Shift 0 · Q161

JEE MainPhysicsElectrostaticsMCQ+4 / −1
On moving a charge of 202020 coulomb by 2cm,2J2cm,2J2cm,2J of work is done, then the potential differences between the points is
  1. A
    0.1V0.1V0.1V
  2. B
    8V8V8V
  3. C
    2V2V2V
  4. D
    0.5V.0.5V.0.5V.
View written solutionFree

Correct answer: A

  1. Use the relation between work, charge, and potential difference

    The electric potential difference is given by V=WqV = \frac{W}{q}V=qW​ where:

    • W=2 JW = 2\,\text{J}W=2J
    • q=20 Cq = 20\,\text{C}q=20C

  2. Substitute the values

    V=220=0.1 VV = \frac{2}{20} = 0.1\,\text{V}V=202​=0.1V

  3. Note about the given distance

    The distance 2 cm2\,\text{cm}2cm is not needed here, because potential difference depends on work done per unit charge: V=WqV = \frac{W}{q}V=qW​

  4. Compare with the options

    • A: 0.1 V0.1\,\text{V}0.1V ✅
    • B: 8 V8\,\text{V}8V
    • C: 2 V2\,\text{V}2V
    • D: 0.5 V0.5\,\text{V}0.5V

Therefore, the correct answer is A.

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