JEE MainPhysicsElectronic DevicesMCQ+4 / −1
Match List I with List II:
| List I | List II | ||
|---|---|---|---|
| A. | Intrinsic semiconductor | I. | Fermi-level near the valence bond |
| B. | n-type semiconductor | II. | Fermi-level in the middle of valence and conduction band. |
| C. | p-type semiconductor | III. | Fermi-level near the conduction band |
| D. | Metals | IV. | Fermi-level inside the conduction band |
Choose the correct answer from the options given below :
- AA-III, B-I, C-II, D-IV
- BA-II, B-I, C-III, D-IV
- CA-I, B-II, C-III, D-IV
- DA-II, B-III, C-I, D-IV
View written solutionFree
Correct answer: D
-
Recall the position of Fermi level for different materials:
- Intrinsic semiconductor: Fermi level lies approximately midway between the valence band and conduction band.
- n-type semiconductor: Due to donor impurities, the Fermi level shifts towards the conduction band.
- p-type semiconductor: Due to acceptor impurities, the Fermi level shifts towards the valence band.
- Metals: The Fermi level lies inside a partially filled conduction band.
-
Now match List I with List II:
- A. Intrinsic semiconductor II. Fermi-level in the middle of valence and conduction band
- B. n-type semiconductor III. Fermi-level near the conduction band
- C. p-type semiconductor I. Fermi-level near the valence band
- D. Metals IV. Fermi-level inside the conduction band
-
Thus the correct matching is:
-
Compare with the given options:
This corresponds to Option D.
-
Comparison with stored correct answer:
Stored correct answer = D
Derived answer = D
Hence, they agree.
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