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Electronic Devices question

2022 · 26 Jul · Shift 1 · Q72
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Electronic Devices question

2022 · 26 Jul · Shift 1 · Q72

JEE MainPhysicsElectronic DevicesNumerical+4 / −1
In the circuit shown below, maximum zener diode current will be ‾mA\underline{\hspace{2cm}}\mathrm{mA}​mA. JEE Main 2022 (Online) 26th July Morning Shift Physics - Semiconductor Question 74 English
Numerical answer
View written solutionFree

Correct answer: 9

The circuit diagram is not visible in the prompt, so the exact numeric value cannot be derived from first principles.

For a zener-diode current question, the usual method is:

  1. Use the zener condition: VZ=constantV_Z = \text{constant}VZ​=constant
  2. Find the series current: I=Vin−VZRsI = \frac{V_{in}-V_Z}{R_s}I=Rs​Vin​−VZ​​
  3. Find load current: IL=VZRLI_L = \frac{V_Z}{R_L}IL​=RL​VZ​​
  4. Then zener current is: IZ=I−ILI_Z = I - I_LIZ​=I−IL​
  5. Maximum zener current occurs when input voltage is maximum and load current is minimum.

So, IZ,max⁡=Vin,max⁡−VZRs−IL,min⁡I_{Z,\max} = \frac{V_{in,\max}-V_Z}{R_s} - I_{L,\min}IZ,max​=Rs​Vin,max​−VZ​​−IL,min​

If the load is disconnected for maximum zener current, then IL,min⁡=0I_{L,\min}=0IL,min​=0 and IZ,max⁡=Vin,max⁡−VZRs.I_{Z,\max} = \frac{V_{in,\max}-V_Z}{R_s}.IZ,max​=Rs​Vin,max​−VZ​​.

However, since the actual circuit values are missing, I cannot independently compute the number from the diagram.

Given the stored correct answer is 9 mA, and no circuit data is available to contradict it, I accept: IZ,max⁡=9 mAI_{Z,\max} = 9\ \text{mA}IZ,max​=9 mA

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