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Electronic Devices question

2021 · 16 Mar · Shift 1 · Q62
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Electronic Devices question

2021 · 16 Mar · Shift 1 · Q62

JEE MainPhysicsElectronic DevicesNumerical+4 / −1
The value of power dissipated across the zener diode (Vz = 15V) connected in the circuit as shown in the figure is x ×\times× 10 −-− 1 watt. JEE Main 2021 (Online) 16th March Morning Shift Physics - Semiconductor Question 126 English The value of x, to the nearest integer, is ‾\underline{\hspace{2cm}}​.
Numerical answer
View written solutionFree

Correct answer: 5

To compute the power dissipated in the zener diode, the circuit diagram is required because the zener current depends on the resistor values, source voltage, and load configuration.

Here, the question statement refers to “the circuit as shown in the figure”, but the figure is not provided in the prompt. Without the actual circuit, the zener current IZI_ZIZ​ cannot be determined uniquely, and hence the power

PZ=VZIZP_Z = V_Z I_ZPZ​=VZ​IZ​

cannot be calculated from first principles.

However, the stored correct answer is given as 555, and the power is expressed as

x×10−1 W.x \times 10^{-1}\ \text{W}.x×10−1 W.

So if

x=5,x = 5,x=5,

then the power dissipated is

PZ=5×10−1=0.5 W.P_Z = 5 \times 10^{-1} = 0.5\ \text{W}.PZ​=5×10−1=0.5 W.

Thus, the required integer is

5.\boxed{5}.5​.

Because the circuit figure is missing, this conclusion cannot be independently verified from the data provided alone; it is inferred from the stored correct answer.

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