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Electronic Devices question

2020 · 3 Sep · Shift 2 · Q59
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  5. /2020 · 3 Sep · Shift 2 · Q59

Electronic Devices question

2020 · 3 Sep · Shift 2 · Q59

JEE MainPhysicsElectronic DevicesMCQ+4 / −1
If a semiconductor photodiode can detect a photon with a maximum wavelength of 400 nm, then its band gap energy is : Planck’s constant h = 6.63 ×\times× 10–34 J.s. Speed of light c = 3 ×\times× 108 m/s
  1. A
    1.5 eV
  2. B
    2.0 eV
  3. C
    3.1 eV
  4. D
    1.1 eV
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