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Electromagnetic Waves question

2019 · 12 Apr · Shift 1 · Q49
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  5. /2019 · 12 Apr · Shift 1 · Q49

Electromagnetic Waves question

2019 · 12 Apr · Shift 1 · Q49

JEE MainPhysicsElectromagnetic WavesMCQ+4 / −1
An electromagnetic wave is represented by the electric field E→=E0n^sin⁡[ωt+(6y−8z)]\overrightarrow E = {E_0}\widehat n\sin \left[ {\omega t + \left( {6y - 8z} \right)} \right]E=E0​nsin[ωt+(6y−8z)]. Taking unit vectors in x, y and z directions to be i^,j^,k^\widehat i,\widehat j,\widehat ki,j​,k, the direction of propagation s^\widehat ss, is :
  1. A
    s^=3i^−4j^5\widehat s = {{3\widehat i - 4\widehat j} \over 5}s=53i−4j​​
  2. B
    s^=−4k^+3j^5\widehat s = {{ - 4\widehat k + 3\widehat j} \over 5}s=5−4k+3j​​
  3. C
    s^=(−3j^+4k^5)\widehat s = \left( {{{ - 3\widehat j + 4\widehat k} \over 5}} \right)s=(5−3j​+4k​)
  4. D
    s^=4j^−3k^5\widehat s = {{4\widehat j - 3\widehat k} \over 5}s=54j​−3k​
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