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Dual Nature of Radiation question

2025 · 8 Apr · Shift 2 · Q74
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Dual Nature of Radiation question

2025 · 8 Apr · Shift 2 · Q74

JEE MainPhysicsDual Nature of RadiationNumerical+4 / −1
An electron is released from rest near an infinite non-conducting sheet of uniform charge density '−σ-\sigma−σ'. The rate of change of de-Broglie wave length associated with the electron varies inversely as nth power of time. The numerical value of n is ‾\underline{\hspace{2cm}}​.
Numerical answer
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Correct answer: 2

  1. Electric field due to an infinite non-conducting sheet

For an infinite sheet with surface charge density −σ-\sigma−σ, the magnitude of electric field is constant:

E=σ2ε0E = \frac{\sigma}{2\varepsilon_0}E=2ε0​σ​

Since the sheet is negatively charged, an electron (charge −e-e−e) experiences force away from the sheet, but we only need the magnitude.

  1. Force and acceleration of the electron

Magnitude of force on the electron:

F=eE=e⋅σ2ε0F = eE = e\cdot \frac{\sigma}{2\varepsilon_0}F=eE=e⋅2ε0​σ​

Hence acceleration is constant:

a=Fm=eσ2ε0ma = \frac{F}{m} = \frac{e\sigma}{2\varepsilon_0 m}a=mF​=2ε0​meσ​

So the electron moves with uniform acceleration from rest.

  1. Momentum as a function of time

Released from rest, so

v=atv = atv=at

Therefore momentum is

p=mv=matp = mv = matp=mv=mat

Thus,

p∝tp \propto tp∝t

  1. de-Broglie wavelength

The de-Broglie wavelength is

λ=hp\lambda = \frac{h}{p}λ=ph​

Since p∝tp \propto tp∝t,

λ∝1t\lambda \propto \frac{1}{t}λ∝t1​

Let

λ=Kt\lambda = \frac{K}{t}λ=tK​

for some constant KKK.

  1. Rate of change of wavelength

Differentiate with respect to time:

dλdt=−Kt2\frac{d\lambda}{dt} = -\frac{K}{t^2}dtdλ​=−t2K​

Hence,

∣dλdt∣∝1t2\left|\frac{d\lambda}{dt}\right| \propto \frac{1}{t^2}​dtdλ​​∝t21​

So the rate of change of de-Broglie wavelength varies inversely as the 2nd power of time.

  1. Final answer

n=2n = 2n=2

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