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Dual Nature of Radiation question

2024 · 4 Apr · Shift 2 · Q68
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Dual Nature of Radiation question

2024 · 4 Apr · Shift 2 · Q68

JEE MainPhysicsDual Nature of RadiationMCQ+4 / −1
Given below are two statements: one is labelled as Assertion A\mathbf{A}A and the other is labelled as Reason R. Assertion A: Number of photons increases with increase in frequency of light. Reason R: Maximum kinetic energy of emitted electrons increases with the frequency of incident radiation. In the light of the above statements, choose the most appropriate answer from the options given below:
  1. A
    A\mathbf{A}A is not correct but R\mathbf{R}R is correct.
  2. B
    A\mathbf{A}A is correct but R\mathbf{R}R is not correct.
  3. C
    Both A\mathbf{A}A and R\mathbf{R}R are correct and R\mathbf{R}R is the correct explanation of A\mathbf{A}A.
  4. D
    Both A\mathbf{A}A and R\mathbf{R}R are correct and R\mathbf{R}R is NOT the correct explanation of A\mathbf{A}A.
View written solutionFree

Correct answer: A

  1. Examine Assertion A

    Assertion A says: Number of photons increases with increase in frequency of light.

    The energy of one photon is E=hνE = h\nuE=hν where hhh is Planck's constant and ν\nuν is frequency.

    For a given amount of radiant energy UUU, the number of photons is N=UhνN = \frac{U}{h\nu}N=hνU​

    So, if frequency ν\nuν increases while total energy remains fixed, the number of photons decreases, not increases.

    Hence, Assertion A is incorrect.

  2. Examine Reason R

    Reason R says: Maximum kinetic energy of emitted electrons increases with the frequency of incident radiation.

    From Einstein’s photoelectric equation, Kmax⁡=hν−ϕK_{\max} = h\nu - \phiKmax​=hν−ϕ where ϕ\phiϕ is the work function.

    Clearly, as ν\nuν increases, Kmax⁡K_{\max}Kmax​ increases linearly (provided ν\nuν is above threshold frequency).

    Hence, Reason R is correct.

  3. Check the relation between A and R

    Since Assertion A is false and Reason R is true, the correct option is: A: A is not correct but R is correct\boxed{\text{A: A is not correct but R is correct}}A: A is not correct but R is correct​

  4. Compare with stored correct answer

    Stored correct answer: A

    My derived answer: A

    So, they agree.

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