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Current Electricity question

2018 · 15 Apr · Shift 2 · Q59
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Current Electricity question

2018 · 15 Apr · Shift 2 · Q59

JEE MainPhysicsCurrent ElectricityMCQ+4 / −1
A copper rod of cross-sectional area A carries a uniform current I through it. At temperature T, if the volume charge density of the rod is ρ\rhoρ, how long will the changes take to travel a distance d ?
  1. A
    2ρ d AI{{2\rho \,d\,A} \over {\rm I}}I2ρdA​
  2. B
    2ρ d AI T{{2\rho \,d\,A} \over {{\rm I}\,T}}IT2ρdA​
  3. C
    ρ d AI {{\rho \,d\,A} \over {{\rm I}\,}}IρdA​
  4. D
    ρ d AI T{{\rho \,d\,A} \over {{\rm I}\,T}}ITρdA​
View written solutionFree

Correct answer: C

  1. Use the relation between current and drift velocity

For a conductor carrying current, the current is I=ρ A vdI = \rho \, A \, v_dI=ρAvd​ where:

  • ρ\rhoρ = volume charge density,
  • AAA = cross-sectional area,
  • vdv_dvd​ = drift speed of charges.

This follows because in time dtdtdt, charge crossing a section is dq=ρ (A vd dt)dq = \rho \,(A\,v_d\,dt)dq=ρ(Avd​dt) so I=dqdt=ρAvd.I = \frac{dq}{dt} = \rho A v_d.I=dtdq​=ρAvd​.

  1. Find the drift speed

From I=ρAvd,I = \rho A v_d,I=ρAvd​, we get vd=IρA.v_d = \frac{I}{\rho A}.vd​=ρAI​.

  1. Time taken to travel distance ddd

If the changes/charge drift travel distance ddd with speed vdv_dvd​, then t=dvd=dI/(ρA).t = \frac{d}{v_d} = \frac{d}{I/(\rho A)}.t=vd​d​=I/(ρA)d​.

Thus, t=ρdAI.t = \frac{\rho d A}{I}.t=IρdA​.

  1. Match with the options

This corresponds to: ρdAI\boxed{\frac{\rho d A}{I}}IρdA​​ which is Option C.

  1. About temperature TTT

Although temperature is mentioned, it does not appear in the required expression because the time depends directly on drift velocity, and with given I,ρ,I, \rho,I,ρ, and AAA, the result is independent of TTT.

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