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Current Electricity question

2006 · Shift 0 · Q118
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Current Electricity question

2006 · Shift 0 · Q118

JEE MainPhysicsCurrent ElectricityMCQ+4 / −1
An electric bulb is rated 220220220 volt -100100100 watt. The power consumed by it when operated on 110110110 volt will be
  1. A
    757575 watt
  2. B
    404040 watt
  3. C
    252525 Watt
  4. D
    505050 Watt
View written solutionFree

Correct answer: C

  1. Use the bulb's rated values to find its resistance

For a bulb rated 220 V220\,\text{V}220V and 100 W100\,\text{W}100W,

P=V2RP = \frac{V^2}{R}P=RV2​

So,

R=V2P=(220)2100=48400100=484 ΩR = \frac{V^2}{P} = \frac{(220)^2}{100} = \frac{48400}{100} = 484\,\OmegaR=PV2​=100(220)2​=10048400​=484Ω

  1. Find the power when operated at 110 V110\,\text{V}110V

Assuming the resistance remains the same,

P′=V′2R=(110)2484=12100484=25 WP' = \frac{V'^2}{R} = \frac{(110)^2}{484} = \frac{12100}{484} = 25\,\text{W}P′=RV′2​=484(110)2​=48412100​=25W

  1. Match with the options

The power consumed is:

25 W25\,\text{W}25W

So the correct option is C.

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