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Current Electricity question

2004 · Shift 0 · Q138
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Current Electricity question

2004 · Shift 0 · Q138

JEE MainPhysicsCurrent ElectricityMCQ+4 / −1
The thermo emfemfemf of a thermocouple varies with temperature θ\thetaθ of the hot junction as E=aθ+bθ2E = a\theta + b{\theta ^2}E=aθ+bθ2 in volts where the ratio a/ba/ba/b is 700∘C.{700^ \circ }C.700∘C. If the cold junction is kept at 0∘C,{0^ \circ }C,0∘C, then the neutral temperature is
  1. A
    1400∘C{1400^ \circ }C1400∘C
  2. B
    350∘C{350^ \circ }C350∘C
  3. C
    700∘C{700^ \circ }C700∘C
  4. D
    No neutral temperature is possible for this termocouple.
View written solutionFree

Correct answer: D

  1. For a thermocouple with cold junction at 0∘C0^\circ C0∘C, the thermo-emf is given by E=aθ+bθ2E = a\theta + b\theta^2E=aθ+bθ2 where θ\thetaθ is the temperature of the hot junction.

  2. The neutral temperature θn\theta_nθn​ is the temperature at which emf is maximum. So, dEdθ=0\frac{dE}{d\theta} = 0dθdE​=0

  3. Differentiate: dEdθ=a+2bθ\frac{dE}{d\theta} = a + 2b\thetadθdE​=a+2bθ Setting this equal to zero: a+2bθn=0a + 2b\theta_n = 0a+2bθn​=0 θn=−a2b\theta_n = -\frac{a}{2b}θn​=−2ba​

  4. Given: ab=700∘C\frac{a}{b} = 700^\circ Cba​=700∘C Hence, θn=−12⋅ab=−7002=−350∘C\theta_n = -\frac{1}{2}\cdot \frac{a}{b} = -\frac{700}{2} = -350^\circ Cθn​=−21​⋅ba​=−2700​=−350∘C

  5. Since the neutral temperature comes out to be negative, it is not physically attainable here for the hot junction when the cold junction is fixed at 0∘C0^\circ C0∘C. Thus, no neutral temperature is possible for this thermocouple in the given situation.

  6. Checking options:

  • A: 1400∘C1400^\circ C1400∘C →\rightarrow→ incorrect
  • B: 350∘C350^\circ C350∘C →\rightarrow→ incorrect sign
  • C: 700∘C700^\circ C700∘C →\rightarrow→ incorrect
  • D: No neutral temperature is possible →\rightarrow→ correct

Therefore, the correct answer is D.

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