Interpret the circuit

The battery is of emf $3\,\text{V}$ and has negligible internal resistance.

From the figure, the external resistors combine to give an equivalent resistance of $R_{\text{eq}} = 2\,\Omega.$

Apply Ohm’s law to the whole circuit

The current drawn from the battery is $I = \frac{V}{R_{\text{eq}}}.$

Substituting $V=3\,\text{V}$ and $R_{\text{eq}}=2\,\Omega$, $I = \frac{3}{2} = 1.5\,\text{A}.$

Match with the given options

$I = 1.5\,\text{A}$ corresponds to Option B.

Comparison with stored correct answer

Stored correct answer: B

Our derived answer: B

Hence, the answer agrees with the stored correct answer.