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Circular Motion question

2022 · 30 Jun · Shift 1 · Q60
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  5. /2022 · 30 Jun · Shift 1 · Q60

Circular Motion question

2022 · 30 Jun · Shift 1 · Q60

JEE MainPhysicsCircular MotionNumerical+4 / −1
A person starts his journey from centre 'O' of the park and comes back to the same position following path OPQO as shown in the figure. The radius of path taken by the person is 200 m and he takes 3 min 58 sec to complete his journey. The average speed of the person is ‾\underline{\hspace{2cm}}​ ms −-− 1. (take π\piπ = 3.14) JEE Main 2022 (Online) 30th June Morning Shift Physics - Circular Motion Question 37 English
Numerical answer
View written solutionFree

Correct answer: 4

  1. Interpret the path

    The person moves along the path O→P→Q→OO \to P \to Q \to OO→P→Q→O.

    From the figure description and statement, the curved part PQPQPQ is a semicircle of radius 200 m200\,\text{m}200m, with OOO as the centre of the park and OPOPOP and QOQOQO as radii.

  2. Find total distance travelled

    Radius r=200 mr = 200\,\text{m}r=200m

    • Straight path OP=200 mOP = 200\,\text{m}OP=200m
    • Curved path PQPQPQ is a semicircle: Length of semicircle=πr=3.14×200=628 m\text{Length of semicircle} = \pi r = 3.14 \times 200 = 628\,\text{m}Length of semicircle=πr=3.14×200=628m
    • Straight path QO=200 mQO = 200\,\text{m}QO=200m

    So total distance is 200+628+200=1028 m200 + 628 + 200 = 1028\,\text{m}200+628+200=1028m

  3. Convert total time into seconds

    Given time =3 min 58 s= 3\,\text{min}\,58\,\text{s}=3min58s 3×60+58=180+58=238 s3\times 60 + 58 = 180 + 58 = 238\,\text{s}3×60+58=180+58=238s

  4. Compute average speed

    Average speed=Total distanceTotal time=1028238\text{Average speed} = \frac{\text{Total distance}}{\text{Total time}} = \frac{1028}{238}Average speed=Total timeTotal distance​=2381028​

    1028238≈4.32 m s−1\frac{1028}{238} \approx 4.32\,\text{m s}^{-1}2381028​≈4.32m s−1

  5. Integer answer

    Since this is an integer-type question, the required answer is 4\boxed{4}4​

  6. Comparison with stored answer

    Stored correct answer is 333, but the calculated average speed is about 4.32 m s−14.32\,\text{m s}^{-1}4.32m s−1, so the integer answer should be 444, not 333.

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