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Center of Mass question

2020 · 6 Sep · Shift 2 · Q51
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  5. /2020 · 6 Sep · Shift 2 · Q51

Center of Mass question

2020 · 6 Sep · Shift 2 · Q51

JEE MainPhysicsCenter of MassNumerical+4 / −1
The centre of mass of solid hemisphere of radius 8 cm is x from the centre of the flat surface. Then value of x is ‾\underline{\hspace{2cm}}​.
Numerical answer
View written solutionFree

Correct answer: 3

  1. Identify the standard result

For a solid hemisphere of radius RRR, the centre of mass lies on its symmetry axis at a distance

3R8\frac{3R}{8}83R​

from the centre of the flat circular face.

  1. Substitute the given radius

Here, R=8 cmR = 8\text{ cm}R=8 cm.

So,

x=3R8=3×88=3 cmx = \frac{3R}{8} = \frac{3\times 8}{8} = 3\text{ cm}x=83R​=83×8​=3 cm
  1. Final answer
3\boxed{3}3​
  1. Comparison with stored answer

Stored correct answer = 333

Our derived answer = 333

So, they agree.

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