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Center of Mass question

2010 · Shift 0 · Q74
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Center of Mass question

2010 · Shift 0 · Q74

JEE MainPhysicsCenter of MassMCQ+4 / −1
Statement - 1 : Two particles moving in the same direction do not lose all their energy in a completely inelastic collision. Statement - 2 : Principle of conservation of momentum holds true for all kinds of collisions.
  1. A
    Statement - 1 is true, Statement - 2 is true; Statement - 2 is the correct explanation of Statement - 1
  2. B
    Statement - 1 is true, Statement - 2 is true; Statement - 2 is not the correct explanation of Statement - 1
  3. C
    Statement - 1 is false, Statement - 2 is true
  4. D
    Statement - 1 is true, Statement - 2 is false
View written solutionFree

Correct answer: A

  1. Analyze Statement 1

In a completely inelastic collision, the two particles stick together after collision.

Let masses be m1,m2m_1, m_2m1​,m2​ and initial velocities be u1,u2u_1, u_2u1​,u2​, both in the same direction.

After collision, common velocity is vvv.

By conservation of momentum,

(m1u1+m2u2)=(m1+m2)v(m_1u_1+m_2u_2)=(m_1+m_2)v(m1​u1​+m2​u2​)=(m1​+m2​)v

So,

v=m1u1+m2u2m1+m2v=\frac{m_1u_1+m_2u_2}{m_1+m_2}v=m1​+m2​m1​u1​+m2​u2​​

Since both u1u_1u1​ and u2u_2u2​ are in the same direction, v≠0v\neq 0v=0 (unless both were zero initially, which is not the intended case).

Hence final kinetic energy is

Kf=12(m1+m2)v2>0K_f=\frac12 (m_1+m_2)v^2 >0Kf​=21​(m1​+m2​)v2>0

So all kinetic energy is not lost.

Therefore, Statement 1 is true.


  1. Analyze Statement 2

The principle of conservation of momentum holds for every collision provided no external force acts on the system.

Thus it is valid for:

  • elastic collisions
  • inelastic collisions
  • completely inelastic collisions

Therefore, Statement 2 is true.


  1. Check whether Statement 2 explains Statement 1

Yes. In Statement 1, the reason all energy cannot be lost is that even in a completely inelastic collision, momentum must still be conserved.

If two particles are moving in the same direction initially, the total initial momentum is nonzero:

pi=m1u1+m2u2>0p_i = m_1u_1 + m_2u_2 > 0pi​=m1​u1​+m2​u2​>0

Therefore after collision the combined body must also have nonzero momentum:

pf=(m1+m2)v=pip_f = (m_1+m_2)v = p_ipf​=(m1​+m2​)v=pi​

So v≠0v\neq 0v=0, and therefore the final kinetic energy cannot be zero.

Thus, Statement 2 is the correct explanation of Statement 1.


  1. Evaluate options
  • A: True, True, and Statement 2 correctly explains Statement 1 ✅
  • B: True, True, but not explanation ❌
  • C: Statement 1 false, Statement 2 true ❌
  • D: Statement 1 true, Statement 2 false ❌

  1. Final Answer

The correct option is:

A\boxed{A}A​
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