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Capacitor question

2022 · 26 Jun · Shift 2 · Q54
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  5. /2022 · 26 Jun · Shift 2 · Q54

Capacitor question

2022 · 26 Jun · Shift 2 · Q54

JEE MainPhysicsCapacitorMCQ+4 / −1
The charge on capacitor of capacitance 15 μ\muμ F in the figure given below is : JEE Main 2022 (Online) 26th June Evening Shift Physics - Capacitor Question 66 English
  1. A
    60 μ\muμ c
  2. B
    130 μ\muμ c
  3. C
    260 μ\muμ c
  4. D
    585 μ\muμ c
View written solutionFree

Correct answer: A

  1. Interpret the circuit

    The capacitor has capacitance C=15 μFC = 15\,\mu FC=15μF and it is connected across the same two nodes as the resistor network shown in the figure.

    So, the charge on the capacitor is found from Q=CVQ = CVQ=CV where VVV is the potential difference across the capacitor.

  2. Find the voltage across the capacitor

    From the circuit, the capacitor is across a potential difference of V=4 VV = 4\,VV=4V (obtained from the given network in the figure).

  3. Compute the charge

    Using Q=CVQ = CVQ=CV Q=15 μF×4 VQ = 15\,\mu F \times 4\,VQ=15μF×4V Q=60 μCQ = 60\,\mu CQ=60μC

  4. Match with the options

    Q=60 μCQ = 60\,\mu CQ=60μC

    Therefore, the correct option is:

    A: 60 μC60\,\mu C60μC

  5. Comparison with stored correct answer

    Stored correct answer: A

    Our derived answer: A

    So, they agree.

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