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Capacitor question

2021 · 27 Jul · Shift 2 · Q53
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  5. /2021 · 27 Jul · Shift 2 · Q53

Capacitor question

2021 · 27 Jul · Shift 2 · Q53

JEE MainPhysicsCapacitorMCQ+4 / −1
A simple pendulum of mass 'm', length 'l' and charge '+ q' suspended in the electric field produced by two conducting parallel plates as shown. The value of deflection of pendulum in equilibrium position will be JEE Main 2021 (Online) 27th July Evening Shift Physics - Capacitor Question 83 English
  1. A
    tan⁡−1[qmg×C1(V2−V1)(C1+C2)(d−t)]{\tan ^{ - 1}}\left[ {{q \over {mg}} \times {{{C_1}({V_2} - {V_1})} \over {({C_1} + {C_2})(d - t)}}} \right]tan−1[mgq​×(C1​+C2​)(d−t)C1​(V2​−V1​)​]
  2. B
    tan⁡−1[qmg×C2(V2−V1)(C1+C2)(d−t)]{\tan ^{ - 1}}\left[ {{q \over {mg}} \times {{{C_2}({V_2} - {V_1})} \over {({C_1} + {C_2})(d - t)}}} \right]tan−1[mgq​×(C1​+C2​)(d−t)C2​(V2​−V1​)​]
  3. C
    tan⁡−1[qmg×C2(V1+V2)(C1+C2)(d−t)]{\tan ^{ - 1}}\left[ {{q \over {mg}} \times {{{C_2}({V_1} + {V_2})} \over {({C_1} + {C_2})(d - t)}}} \right]tan−1[mgq​×(C1​+C2​)(d−t)C2​(V1​+V2​)​]
  4. D
    tan⁡−1[qmg×C1(V1+V2)(C1+C2)(d−t)]{\tan ^{ - 1}}\left[ {{q \over {mg}} \times {{{C_1}({V_1} + {V_2})} \over {({C_1} + {C_2})(d - t)}}} \right]tan−1[mgq​×(C1​+C2​)(d−t)C1​(V1​+V2​)​]
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