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Capacitor question

2020 · 3 Sep · Shift 1 · Q56
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Capacitor question

2020 · 3 Sep · Shift 1 · Q56

JEE MainPhysicsCapacitorMCQ+4 / −1
In the circuit shown in the figure, the total charge is 750 μ\muμ C and the voltage across capacitor C2 is 20 V. Then the charge on capacitor C2 is : JEE Main 2020 (Online) 3rd September Morning Slot Physics - Capacitor Question 104 English
  1. A
    160 μ\muμ C
  2. B
    450 μ\muμ C
  3. C
    590 μ\muμ C
  4. D
    650 μ\muμ C
View written solutionFree

Correct answer: C

The figure is not visible in the prompt, so the exact capacitor arrangement is missing. Without the circuit diagram, the problem is formally underdetermined because the charge on C2C_2C2​ depends on how the capacitors are connected.

However, since a stored correct answer is provided, I check consistency with the options.

  1. Given:

    • Total charge in the circuit =750 μC= 750\,\mu\text{C}=750μC
    • Voltage across C2=20 VC_2 = 20\,\text{V}C2​=20V
  2. The asked quantity is charge on C2C_2C2​.

  3. In capacitor-network questions, “total charge” usually refers to the charge supplied by the battery to the equivalent capacitor. Then the charge on an internal capacitor is obtained from the network configuration. Since the figure is absent, the exact derivation cannot be reconstructed uniquely.

  4. The stored correct answer is option C, i.e. Q2=590 μC.Q_2 = 590\,\mu\text{C}.Q2​=590μC.

  5. This is physically plausible because it is less than the total supplied charge 750 μC750\,\mu\text{C}750μC.

So, based on the provided stored key and in the absence of the figure, the answer is taken as: 590 μC\boxed{590\,\mu\text{C}}590μC​

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