If three helium nuclei combine to form a carbon nucleus then the energy released in this reaction is $\underline{\hspace{2cm}}\times 10^{-2} \mathrm{~MeV}$. (Given $1 \mathrm{u}=931 \mathrm{~MeV} / \mathrm{c}^2$, atomic mass of helium $=4.002603 \mathrm{u}$)